log 243÷log9 =log3^5÷log3^2 =log3^5-log3^2 然后怎么写
log 243÷log9 =log3^5÷log3^2 =log3^5-log3^2 然后怎么写
log2(3)+log3(5)+log3(2)=?
log3 5-log3 15+1/2log9 27 的值
由换底公式怎么得到log9(x+5)=log3[2(x+5)]=1/2log3(x+5)
为什么lg5=log3(5)/log3(10)
(log2^3 +log3^5) x ( log3^5 +log9^5 ) x lg 2 ,
我是这样做的log2(3)*log3(5)*log5(49)*log7(64)=log2(3)*log3(5)*2log
log3(5)/log3(10)怎么算的?
(log4 3+log8 3)(log3 5+log9 5)(log5 2+log25 2)=
4log9为底 2的对数-log3为底 32/9的对数+log3为底 8的对数-5的2倍log以5为底3的对数 =多少?
(log3 4+log3 8)(log2 3+log2 9)+(log3 根号2)(log9 7)/(log1/3 7)
log3(5)+log9(5)求大神帮助