两点式方程如何化为截距式方程
来源:学生作业帮 编辑:大师作文网作业帮 分类:数学作业 时间:2024/11/18 12:51:43
两点式方程如何化为截距式方程
(y-y1)/(x-x1)=(y2-y1)/(x2-x1) (直线两点式方程)
(y-y1)(x2-x1)=(x-x1)(y2-y1)
(x2-x1)y-(x2-x1)y1=(y2-y1)x-(y2-y1)x1
(y1-y2)x+(x2-x1)y=(x2-x1)y1-(y2-y1)x1
(y1-y2)x+(x2-x1)y=x2y1-x1y2
(y1-y2)x/(x2y1-x1y2)+(x2-x1)y/(x2y1-x1y2)=1
x/[(x2y1-x1y2)/(y1-y2)]+y/[(x2y1-x1y2)/(x2-x1)]=1(直线的截距式)
(y-y1)(x2-x1)=(x-x1)(y2-y1)
(x2-x1)y-(x2-x1)y1=(y2-y1)x-(y2-y1)x1
(y1-y2)x+(x2-x1)y=(x2-x1)y1-(y2-y1)x1
(y1-y2)x+(x2-x1)y=x2y1-x1y2
(y1-y2)x/(x2y1-x1y2)+(x2-x1)y/(x2y1-x1y2)=1
x/[(x2y1-x1y2)/(y1-y2)]+y/[(x2y1-x1y2)/(x2-x1)]=1(直线的截距式)