(1/2+1/3+1/4+.+1/2004)(1+1/2+.+1/2004)-(1+1/2+.+1/2005)(1/2+
1/1*2+1/2*3+1/3*4+.+1/2004*2005+1/2005*2006
1/1*2+1/3*4+1/4*5+...+1/2004*2005+1/2005*2006,
计算:(1/2006-1)(1/2005-1)(1/2004)… (1/3-1)(1/2-1).
1*2/1+2*3/1+3*4/1+.+2004*2005/1=
1/2*1+1/2*3+1/3*4+.+1/2004*2005=?
(1-1/2-1/3-1/4..-1/2004)*(1+1/2+1/3+1/4+...+1/2005)-(1-1/2-1
(1-2²/1)×(1-3²/1)×...(1-2004²/1)×(1-2005²
计算:(2+1/2003+1/2004=1/2005+1/2006)+(1/2003+1/2004+1/2005+1/2
计算:(2+1/2003+1/2004)x(1/2003+1/2004+1/2005)—(2+1/2003+1/2004
(1-1/2004)+(2-1/2004*2)+(3-1/2004*3)+.+(2004-1/2004*2004)
(1/2005-1)(1/2004-1)(1/2003-1)…(1/2-1)=?
1.计算(1/2006-1)(1/2005-1)(1/2004-1)…(1/2-1) ( / 分数线)