(1+0.228-0.21)×(0.228-0.21+0.2003)-(1+0.228-0.21+0.2003)×(0.
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(1+0.228-0.21)×(0.228-0.21+0.2003)-(1+0.228-0.21+0.2003)×(0.228-0.21)简便解法
这是预初一的题,但是不要告诉我去用计算机去做,
这是预初一的题,但是不要告诉我去用计算机去做,
(1+0.228-0.21)×(0.228-0.21+0.2003)-(1+0.228-0.21+0.2003)×(0.228-0.21)
=(1+0.228-0.21)×(0.228-0.21)+(1+0.228-0.21)×0.2003
-(1+0.228-0.21)×(0.228-0.21)-0.2003×(0.228-0.21)
=(1+0.228-0.21)×0.2003-0.2003×(0.228-0.21)
=0.2003× 【(1+0.228-0.21)-(0.228-0.21)】
=0.2003×1
=0.2003
=(1+0.228-0.21)×(0.228-0.21)+(1+0.228-0.21)×0.2003
-(1+0.228-0.21)×(0.228-0.21)-0.2003×(0.228-0.21)
=(1+0.228-0.21)×0.2003-0.2003×(0.228-0.21)
=0.2003× 【(1+0.228-0.21)-(0.228-0.21)】
=0.2003×1
=0.2003
计算下面各题,能简算的要简算 (1) 15×32-4050÷50(2)×0.79 +×0.21
(1+0.21+0.32)*(0.21+0.32+0.43)-(1+0.21+0.32+0.43)*(0.21+0.32
计算(1+0.21+0.32)x(0.21+0.32+0.43)-(1+0.21+0.32+0.43)x(0.21+0.
(9999+9997+.+9001)-(1+3+.+999)
(2010+2008+2006+.+2)-(1+3+5+.+2009)
(1+0.21+0.32)*(0.21+0.32+0.43)-(1+0.21+0.32+0.43)*(0.21+0.32
1.(2+4+6+.1984+1986+1988)-(1+3+5+.+1985+1987)=?
(+1)+(-2)+(+3)+(-4)++(+99)+(-100)等于几?
计算:(+1)+(-3)+(+5)+(-7)+⋯+(+97)+(-99)
已知关于x的一元二次方程x2+(m+3)x+m+1=0. (
(1+二分之一+三分之一+四分之一)×
(1+3+7+…+1991)-(2+4+6+8+…+1990)=