点D,E在△abc的边bc上,AD=AE,∠BAD=∠CAE,求证:AB=AC
已知:如图,点D、E在△ABC的边BC上,AD=AE,∠BAD=∠CAE.求证:AB=AC
已知:如图,点D、E在△ABC的边BC上,AD=AE,∠BAD=∠CAE.求证:AB=AC【用三线合一】
已知:如图,点D,E在三角形ABC的边BC上,AD=AE,角BAD=角CAE 求证:AB=AC 要
如图 点D,E在△ABC的边BC上,AB=AC,AD=AE.求证∠BAD=∠CAE.(好像要用三线合一的性质)
如图,在△ABC中,点D是BC上的一点,且AB=AD,AC=AE,∠BAD=∠CAE.
已知:如图,点D、E在△ABC的边BC上,AD=AE,∠BAD=∠CAE
如图10,已知点D、E、F在△ABC的边BC上,AB=AC,AD=AE,DF=EF,试着说明角BAD=角CAE
点D.E在△ABC的边BC上,AD=AE,BD=EC,求证:AB=AC
已知:如图,在△ABC中,AB=AC,D.E为BC上的两点,且AD=AE.求证:角BAD=角CAE.用“三线合一”
如图,D,E是三角形ABC的边BC上的两点,AB=AC,AD=AE,试用一种方法说明角BAD=角CAE
点D E在三角形ABC的边BC上 AB=AC AD=AE 求证BD=CE
点D,E在三角形ABC的边BC上,AB=AC,AD=AE,求证BD=CE