有关能量守恒的I push a cart up with a constant force up a slope to
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有关能量守恒的
I push a cart up with a constant force up a slope to a height of 1/4 meter.The mass of the cart is 1/4 kg.The cart moves 1/2 meter along the table as I do this.After I let it go,the cart continues up the slope
until it reaches a height of 1/2 meter and then starts back down.What was the magnitude of the force with which I pushed the cart?
45/√5 、
I push a cart up with a constant force up a slope to a height of 1/4 meter.The mass of the cart is 1/4 kg.The cart moves 1/2 meter along the table as I do this.After I let it go,the cart continues up the slope
until it reaches a height of 1/2 meter and then starts back down.What was the magnitude of the force with which I pushed the cart?
45/√5 、
翻译 我用恒力将一辆车推上高1/4米的斜坡.小车的质量是1/4千克.当我这样做的时候小车在斜面上移动了1/2米.小车继续在斜面上滑行.直到小车到达1/2米的高度时开始返回.求我对小车施加的力是多少牛.
有两种解法.
一.根据机械能守恒得.F*S=mg*h 其中S=0.5m mg=5/2N h=1/2m
所以解得F=5/2N
二.由高1/4米,长1/2米得斜面倾斜角为30度.2*(F-mg/2)/m*L=g/2*2*L 因为前后两过程的末速度相同.
解得F=5/2N
上面的解答是当斜面的摩擦因素为零时的答案
若斜面粗糙的话,那么摩擦力大于零小于5/2N所以答案为 5/2N
有两种解法.
一.根据机械能守恒得.F*S=mg*h 其中S=0.5m mg=5/2N h=1/2m
所以解得F=5/2N
二.由高1/4米,长1/2米得斜面倾斜角为30度.2*(F-mg/2)/m*L=g/2*2*L 因为前后两过程的末速度相同.
解得F=5/2N
上面的解答是当斜面的摩擦因素为零时的答案
若斜面粗糙的话,那么摩擦力大于零小于5/2N所以答案为 5/2N
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