请数学能手来看看这题lim{(1/N2+1)+(2/n2+2)+.+(n/n2+n)}n2是n的平方,n趋向无穷是求极限
求 证Lim ( n/ n2+1) + (n/ n2+2) +( n/ n2+3).+(n/n2+n)当n趋向无穷时的极
求极限lim((n+1)/(n2+1)+(n+2)/(n2+2)+...+(n+n)/(n2+n)),n趋近无穷
大一求极限lim(n/(n2+1)+n/(n2+2^2)+……+n/(n2+n2))
1.求lim[1/(n2+n+1)+2/(n2+n+2)+.+n/(n2+n+n)][n趋于无穷][n2为n的平方]
求lim【1/(n2+π)+1/(n2+2π)+...+1/(n2+nπ)】(n趋向于正无穷)
高数极限题:用极限定义,证明:lim n2+n+6/n2+5=1 n趋向于无穷.其中n2就是n的平方
计算lim(1/n2+1+2/n2+1+3/n2+1+...+n/n2+1)
请问如何证明lim(n→∞)[n/(n2+n)+n/(n2+2n)+…+n/(n2+nn)]=1,
(1-1/n2)n2【一减去n的平方分之一的n的平方次方】当n趋于无穷时的极限是?1/e还是1.
2N N2 2N2
lim(√(n2+2n)-n) 当n趋向无穷时
Lim bn( n趋向无穷大) [( 1/ n2+1) + (2/ n2+1) +( 3/ n2+1) +.(2n/ n