化简sin^4x+sin^2xcos^2x+cos^2x=?(请写过程)
sin^2x+cos^2x)(sin^4x-sin^2xcos^2x+cos^4x) =sin^4x-sin^2xcos
化简cos^4x+sin^2xcos^2x+sin^2x
(1-(sin^4x-sin^2xcos^2x+cos^4x)/sin^2x +3sin^2x
求函数f(x)=(sin^4x+cos^4x+sin^2xcos^2x)/2
求函数y=2sin xcos x+2sin x+2cos x+4的值域
求函数f(x)=(sin⁴x+cos⁴x+sin²xcos²x)/(2-si
证明sin4次方x+cos四次方x=1-2sin²xcos²x
已知函数f(x)=a(cos^2 x+sin xcos x)+b.
已知f(x)=√3sinωxcosωx+cosωx^2,函数f(x)的最小正周期为π,求ω.(请把过程写详细一点,谢谢)
求sin^4x+cos^4x+4sin^2xcos^2x-1的最小正周期及值域.
证明sin四次方x+cos四次方x=1-2sin平方xcos平方x
f(x)=a(sin^6x+cos^6x)+b(sin^4x+cos^4x)+6sin^2xcos^2x的值与x无关且等