(1/2+1/3+...+1/2004)(1+1/2+1/3+...+1/2003)-(1+1/2+1/3+...+1/
来源:学生作业帮 编辑:大师作文网作业帮 分类:数学作业 时间:2024/11/18 03:08:24
(1/2+1/3+...+1/2004)(1+1/2+1/3+...+1/2003)-(1+1/2+1/3+...+1/2004)(1/2+1/3+...+1/2003)
(1/2+1/3+...+1/2004)(1+1/2+1/3+...+1/2003)-(1+1/2+1/3+...+1/2004)(1/2+1/3+...+1/2003)
=(1/2+1/3+...+1/2004)(1/2+1/3+...+1/2003)+(1/2+1/3+...+1/2004)-(1/2+1/3+...+1/2004)(1/2+1/3+...+1/2003)-(1/2+1/3+...+1/2003)
=(1/2+1/3+...+1/2004)-(1/2+1/3+...+1/2003)
=1/2004
=(1/2+1/3+...+1/2004)(1/2+1/3+...+1/2003)+(1/2+1/3+...+1/2004)-(1/2+1/3+...+1/2004)(1/2+1/3+...+1/2003)-(1/2+1/3+...+1/2003)
=(1/2+1/3+...+1/2004)-(1/2+1/3+...+1/2003)
=1/2004
化简(1/2+1/3+...1/2003)*(1+1/2+...1/2004)-(1+1/2+...1/2004)*(1
(1/2+1/3+.+1/2004)乘(1+1/2+.+1/2003)减(1+1/2+.1/2004)乘(1/2+1/3
(1-1/2-1/3-1/4-……-1/2003)(1/2+1/3+1/4+...+1/2004)-(1-1/2-1/3
(根号3+1)^2004-2(根号3+1)^2003-2(根号3+1)^2002+2004
1.(1/2+1/3+…+1/2003)(1+1/2+1/3+…+1/2004)-(1+1/2+1/3+…+1/2003
(1-1/2)(1/3-1)(1-1/4)(1/5-1)……(1/2003-1)(1-1/2004)
1/1*2+1/2*3+1/3*4.+1/2003*2004
简算(1/2+1/3+...+1/2003)(1+1/2+1/3+...+1/2004)-(1+1/2+1/3+...1
数学题解答|1/3-1/2|+|1/4-1/3|+|1/5-1/4|+…+|1/2004-1/2003|
计算【1/3-1/2】+【1/4-1/3】+【1/5-1/4】+……+【1/2004-1/2003】
S=根号(1+1/1^2+1/2^2)+根号(1+1/2^2+1/3^2)+.+根号(1+1/2003^2+1/2004
(1-1/2004)+(2-1/2004*2)+(3-1/2004*3)+.+(2004-1/2004*2004)