log9(16) ×log2(27)=6步骤

来源：学生作业帮编辑：大师作文网作业帮分类：数学作业时间：2024/11/20 08:17:38

log9(16) ×log2(27)
=lg16/1g9×lg27/lg2
=(lg16×lg27)/(lg9×lg2)
=(lg2^4×lg3^3)/(lg3^2×lg2)
=(4lg2×3lg3)/(2lg3×lg2)
=4×3/2
=6

log2 根号2+log9 27+4^log4 13=? （log2 3+log4 27）*（log3 4+log9 8）= log2^根号下2+log9^27+4^(log4^13) (log2 3+log4 9+log8 27+...+log2^n 3^n）log9 32的N次方根计算（log2 3+log4 9+log8 27+……+log2^n 3^n）log9 n次根号3 log2 √2 +log9 27 +4∧log4 13的值为 Log2⒊log3⒋log4ⅹ=log9⒊求x的值若log2^3×log3^4×log4^x=log9^3 ,求x 高中数学.快点哈log2的三次幂=a 求log9的八次幂? log9^8×log4^27=____. (log2 3+log4 9.+log8 27+.+log(2^n底)(3^n))log9 n次根号32 (log2（3）+log4（9）+……+log2^n（3^n）)·log9（n次根号8）=