log2^根号下2+log9^27+4^(log4^13)

log2^根号下2+log9^27+4^(log4^13) log2 根号2+log9 27+4^log4 13=? log4(3)*log9(2)+log2(4倍根号下64) log9(32)*log64(2 log2 √2 +log9 27 +4∧log4 13的值为 (log3,4+log9,4)log4,3—log2,2根号2 这怎么解答了 [log2(3)+log4(9)][log3(4)+log9(2)]等于 (log2 3+log4 9.+log8 27+.+log(2^n底)(3^n))log9 n次根号32 计算（log2 3+log4 9+log8 27+……+log2^n 3^n）log9 n次根号3 log4为底3次方乘以log9为底2次方+log2为底4倍根号下32+16的4分之3次方-2.83分之2次方 （log2 3+log4 27）*（log3 4+log9 8）= (log4^3+log8^3)*(log3^2+log9^2)-log2^4次√32 log4为底3的对数*log9为底2的对数+log2为底（4倍根号35）的对数