1/(x^2+x-2)-1/(x^2+7x+10)=2的解答过程
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1/(x^2+x-2)-1/(x^2+7x+10)=2的解答过程
帮忙解答啊!
帮忙解答啊!
x^2+x-2 = ( x - 1)(2 + x)
x^2+7x+10 = (2 + x) (5 + x)
1/(x^2+x-2)-1/(x^2+7x+10) = 2
(5 + x) - ( x - 1) = 2( x - 1)((2 + x) (5 + x)
6 = 2( x - 1)((2 + x) (5 + x)
3 = ( x - 1)((2 + x) (5 + x)
x = -4.81691,x = -2.33761,x = 1.15452
x^2+7x+10 = (2 + x) (5 + x)
1/(x^2+x-2)-1/(x^2+7x+10) = 2
(5 + x) - ( x - 1) = 2( x - 1)((2 + x) (5 + x)
6 = 2( x - 1)((2 + x) (5 + x)
3 = ( x - 1)((2 + x) (5 + x)
x = -4.81691,x = -2.33761,x = 1.15452
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