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知函数y=sin²x+sin2x+2cos²x,求(1)函数的最小值及此时的x集合; (2)函数的单
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求函数y=[sin2x+sin(2x+π/3)]/[cos2x +cos(2x+π/3)]的最小正周期
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(2010•河西区二模)要得到函数y=sin(2x+2π3)得图象,只需将y=sin2x的图象( )