来源：学生作业帮 编辑：大师作文网作业帮 分类：数学作业 时间：2024/10/08 05:21:11
立体几何题求解答,
PA⊥ABCD==>PA⊥CD (1)
CD⊥AC (2)
(1)(2)==>CD⊥PAC
E在PC上 AE在PAC上 CD⊥AE
AB=BC ∠ABC=60° ==>AC=AB=BC=PA
PA⊥ABCD==>PA⊥AC==> △PAC为等腰RT△
E为斜边中点,==>AE⊥PC
AE⊥CD==>AE⊥PCD ==>AE⊥PD (3)
PA⊥ABCD ==>PA⊥AB (4)
AB⊥AD(5)
(4)(5)==>AB⊥PAD==AB⊥PD (6)
(3)(6)==>PD⊥ABE
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