为什么sinx/2+√3cosx/2=2sin(x/2+π/3)?
sinx+cosx/sinx-cosx=2 求sinx/cos^3x +cosx/sin^3x
已知(sinx+cosx)/(sinx-cosx)=3,求tanx,2sin²x+(sinx-cosx)&su
已知sinx=2/3,求(cosx-sinx/cosx+sin)+(cosx+sin/cosx-sinx)的值.
已知函数f(x)=2cosx*sin(x+π/3)-√3sin^2x+sinx*cosx
f(x)=2cos*sin(x+π/3)-^3sin^2x+sinx*cosx
已知sinx+cosx/sinx-cosx=3,求tanx,2sin^2x+(sinx-cosx)^2的值
利用cosx=sin(π/2-x),sin'x=cosx,证明(cosx)'=-sinx
已知函数f(x)=2cosx*sin(x+π/3)-根号3sin^2x+sinx*cosx
设f(x)=2cosx.sin(x+π/3)-根号3 sin平方x+sinx.cosx
sinx+cosx=√2sin(x+π/4)
已知函数f(x)=[2sin(x+π/3)+sinx]cosx-√3sin²x,x∈R
求证 sin^2x/(sinx-cosx)-(sinx+cosx)/tan^2 x-1=sinx+cosx