A highly volatile substance initially has a mass of 1200g an
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A highly volatile substance initially has a mass of 1200g and its mass is reduced by 12% each second.
Q1.Write a formula that gives the mass of the substance(m) at time(t) seconds.
Q2.Rearrange this formula to make t the subject.
Q3.What mass remains after 10 seconds,correct to two decimal places?
Q4.Calculate how long (to the nearest seconds) it takes until the mass is 10 grams.
Q5.After how many seconds (to the nearest seconds) is the mass less than 1 gram?
题的意思我知道
Q1.Write a formula that gives the mass of the substance(m) at time(t) seconds.
Q2.Rearrange this formula to make t the subject.
Q3.What mass remains after 10 seconds,correct to two decimal places?
Q4.Calculate how long (to the nearest seconds) it takes until the mass is 10 grams.
Q5.After how many seconds (to the nearest seconds) is the mass less than 1 gram?
题的意思我知道
1、m=1200*(1-12%)^t
2、t=log[m-1200*(1-12%)]
3、当t=10时,m=1200*(1-12%)^10= 自己用计数器算
4、当m=10时,t=log[10-1200*(1-12%)]= 自己用计数器算(注意t为整数,是小数时四舍五入)
5、当m=1时,t=log[1-1200*(1-12%)] (注意t为整数,t的取值要小于等于计算出来的值)
2、t=log[m-1200*(1-12%)]
3、当t=10时,m=1200*(1-12%)^10= 自己用计数器算
4、当m=10时,t=log[10-1200*(1-12%)]= 自己用计数器算(注意t为整数,是小数时四舍五入)
5、当m=1时,t=log[1-1200*(1-12%)] (注意t为整数,t的取值要小于等于计算出来的值)
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