设f(t)是二次可微函数且f''(t)不等于0 x=f'(t),y=tf'(t)-f(t),求dy/dx,d^2y/dx
设f(t)是二次可微函数且f''(t)不等于0 x=f'(t),y=tf'(t)-f(t),求dy/dx,d^2y/dx
设f(x)连续,Y=∫0~X tf(x^2-t^2)dt 则dy/dx=?
设y=f(x,t),而t是方程F(x,y,t)=0所确定的x,y的函数(F't(x,y,t)≠0),求dy/dx..
x=f'(t).y=tf'(t)-f(t),设f"(t)存在且不等于零,求二阶导数
一道导数的题目,x=f '(t)y=tf '(t)-f(t)dy/dx=tf''(t)/f"(t)=t为什么dy/dx的
f(x)为连续函数,∫(1-2)f(x)dx=1,F(t)= ∫(1-t)[f(y) ∫(y-t)f(x)dx]dy,则
设f(t)=∫e^(-x^2)dx,求∫tf(t)dt=?
x=f(t) y=g(t) 为什么dy/dx=(dy/dt)*(dt/dx)
F(t)=∫上标t下标1dy∫上标t下标y f(x)dx,且f(x)为连续函数则F'(2)=?
设f(x,y,z)可微,对一切t不等于0,有f(tx,ty,tz)=tf(x,y,z),试证:xf'(x)+yf'(y)
设f(x)连续,d/dx∫上标x下标0tf(x^2-t^2)dt=?
求参数方程导数x=f'(t),y=tf'(t)-f(t)