由y=x^2+4\x^2+1得x^2=y+4\y+ 1
由y=x^2+4\x^2+1得x^2=y+4\y+ 1
{3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1
已知4x=9y求(1)x+y/y (2)y-x/2x
化简[(3x+4y)^2-(2x+y)(2x-y)+(-x+y)(5x-y)]除以-2y,其中x=-1,y=1
已知x=1/3,y=-1/2,求代数式x-(x+y)+(x+2y)-(x+3y)+(x+4y)-(x+5y)+...-(
已知x²+y²+5=2x+4y,求【2x²-(x-y)(x-y)】【(x+y-1)(x-y
y=f(x)由x^2+3y^4+x+2y=1所确定,求dy/dx
用代入法解方程组3x+4y=2,2x-y=5使得带入后化简比较容易变形是()1.由1得,x=2-4y/3 2.由1得y=
[(y-2x)(-2x-y)-4(x-2y)²]*2y,其中x=1,y=2
解方程组4x+y=53x-2y=1得x=1y=1,把
十万分,[3x+2y]/2=[2x+y]/3=[x-y+1]/4 解得.
[(2x+y)^2+(y+2x)(y-2x)-2y(4x-y)]/4y,其中x=1/2,y=1/3