y=xsiny+1 求dy/dx
y=xsiny+1 求dy/dx
验证积分I=∫(e^xsiny-2y+1)dx+(e^xcosy-2x)dy与路径无关
求∫(e∧xsiny-y)dx+(e∧xcosy-1)dy,其中L为点A(a,0)到点B(0,0)的上半圆周
求∫(e∧xsiny-y)dx+(e∧xcosy-1)dy,其中L为点A(2,0)到点B(0,0)的圆周x^2+y^2=
计算(e^xsiny-3y+x^2)dx+(e^xcosy-x)dy,其中L为:2x^2+y^2=1
∫ (e^xsiny-my)dx+(e^xcosy-m)dy其中L是按逆时针方向从圆周(x-1)^2+y^2=1上点A(
y=1+xe^y,求dy/dx
求导数,y=1+xe^y,求dy/dx
设y+xe^y=1,求dy/dx
设y=1+xe^y,求dy/dx
cos(x+y)+y=1 求dy/dx
y=xe^y 求dy/dx