lim(x->0)[x/sin(x)]=?即高数中两个重要极限中的前一个{lim(x->0)[sin(x)/x]=1}反
lim(x->0)[x/sin(x)]=?即高数中两个重要极限中的前一个{lim(x->0)[sin(x)/x]=1}反
求极限 ((sin(x^3+x^2-x)+sin x) /x x→0 已知lim sinx/x=1
求极限,lim x趋于0 x * sin 1/x
求极限lim(x-->0)x^2 sin(1/x),
极限lim【sin(x+π)】/x x趋向于0 就能推出lim【sin(x+π)】/x =lim(-sinx)/x =-
lim x->0(sqrt(sin(1/x^2)) 求极限
用∈-N极限定义证明x→o lim x*sin(1/x)=0
求极限 lim sin(x^2 * sin (1/x))/x x->0
求极限lim(x-->0) (tanX-sinX)/[(sin^3)X]
求极限 lim (x->0) sin(sinx)/x
求极限lim(x趋于0时)sin(sinx)/x
有界函数极限存在么类似:lim(x→0)(sin(1/x)=