十字相乘法解题1)2x2-5x-12; (2)3x2-5x-2; (3)6x2-13x+5; (4)7x2-19x-6;
来源:学生作业帮 编辑:大师作文网作业帮 分类:数学作业 时间:2024/09/29 10:20:41
十字相乘法解题
1)2x2-5x-12; (2)3x2-5x-2;
(3)6x2-13x+5; (4)7x2-19x-6;
(5)12x2-13x+3; (6)4x2+24x+27.
(1)6x2-13xy+6y2; (2)8x2y2+6xy-35;
(3)18x2-21xy+5y2
1)2x2-5x-12; (2)3x2-5x-2;
(3)6x2-13x+5; (4)7x2-19x-6;
(5)12x2-13x+3; (6)4x2+24x+27.
(1)6x2-13xy+6y2; (2)8x2y2+6xy-35;
(3)18x2-21xy+5y2
2x2-5x-12=(2x+3)*(x-4) 3x2-5x-2=(3x+1)*(x-2)
6x2-13x+5=(2x-1)*(3x-5) 7x2-19x-6=(x-3)*(7x+1)
12x2-13x+3=(2x-1)*(6x-3) 4x2+24x+27=(2x+9)*(2x+3)
6x2-13xy+6y2=(2x-3y)*(3x-2y) 8x2y2+6xy-35=(2xy-5)*(4xy+7)
18x2-21xy+5y2=(3x-y)*(6x-5y)
6x2-13x+5=(2x-1)*(3x-5) 7x2-19x-6=(x-3)*(7x+1)
12x2-13x+3=(2x-1)*(6x-3) 4x2+24x+27=(2x+9)*(2x+3)
6x2-13xy+6y2=(2x-3y)*(3x-2y) 8x2y2+6xy-35=(2xy-5)*(4xy+7)
18x2-21xy+5y2=(3x-y)*(6x-5y)
十字相乘法解题1)2x2-5x-12; (2)3x2-5x-2; (3)6x2-13x+5; (4)7x2-19x-6;
解方程:1/x2+x +1/x2+3x+2 +1/x2+5x+6 +1/x2+7x+12 +1/x2+9x+20=5/x
(x2-3)(x2-2)-2十字相乘法做 (x2+3x+2)(x2+7x+12)-24十字相乘法做
(1)x2+12x=0; (2)4x2-1=0; (3)x2=7x (4)x2-4x-21=0; (5)(x-1)(x+
1/(x2+3x+2)+1/(x2+5x+6)+1/(x2+7x+12)=1/(x+4)
1/(x2+x)+1/(x2+3x+2)+1/(x2+5x+6)+1/(x2+7x+12)=4/21
用公式法解下列方程: (1) 2 x2+x-6=0; (2) 5x2-4x-12=0; (3) 4x2+4x+10=1-
4x4×x2×x-(﹣x)3×(﹣x)4-2x2×x5
先化解,再求值:【1/(x2+3x+2)+1/(x2+5x+6)+1/(x2+7x+12)】/1/(x2+9x+20),
x2+﹙1/6﹚x-1/3=0②x2-2x=3③x2-4x-2=0④-2x²-x+7=0⑤3x²-x
5x2+4-3x2-5x-2x2-5+6x.
解分式方程:2/x2+5x+6 + 3/x2+x-6=4/x2-4