设x=lnx,y=t∧3,求dy/dX?

设x=lnx,y=t∧3,求dy/dX? y=x+lnx,求dx/dy 设y=x+lnx,则dx/dy= 设y=f((2x-1)/(x+1)),f'(x)=lnx^(1/3),求dy/dx 设函数Y=LNX平方,求DX分之DY|X=1? 求x*(dy/dx)=lnx-y的通解 已知y=x+lnx,求dy/dx 急.dy/dx-y/x=lnx y=(lnx)∧y,求dy/dx=? 求微积分方程（y/x）*dx+(y^3+lnx)dy=0的通解 设y=y(x)由方程xy+lnx+lny=1所确定,求dy/dx. 设 x/y=ln(y/x) ,求 dy/dx