化简 [Sin(π+α)\tan(π+α)] ×[ cot(2π-α)\cos(π+α)]×[sec(2π-α)\csc

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化简 [Sin(π+α)\tan(π+α)] ×[ cot(2π-α)\cos(π+α)]×[sec(2π-α)\csc(π-α)]

$化简 [Sin(π+α)\tan(π+α)] ×[ cot(2π-α)\cos(π+α)]×[sec(2π-α)\csc$

[Sin(π+α)\tan(π+α)] ×[ cot(2π-α)\cos(π+α)]×[sec(2π-α)\csc(π-α)]
= [(-sinα)\tanα] ×[(-cotα)\(-cosα)]×[secα\cscα]
= [(-sinα)×cosα\sinα] ×[(cosα\sinα)\cosα)]×(sinα\cosα)
=-cosα×(1\sinα)×(sinα\cosα)
=-1

化简 [Sin(π+α)\tan(π+α)] ×[ cot(2π-α)\cos(π+α)]×[sec(2π-α)\csc π/2的6个三角函数值 sin cos tan sec csc cot 证明tan^2α-cot^2α/sin^2α-cos^2α=sec^2α+csc^2α 已知tan^2α+cot^2α+sec^2α+csc^2α=7,则sinαcosα 求证：(tanα -cotα )/(secα -cscα )=sinα +cosα 证明 sin^2αtanα+cos^2αcotα+2sinαcosα=secαcscα 已知tanα=2,求cos(α-7π/2)+2sin(π-3α)/csc(π+α)+sec(π/2+α）的值化简：[cos(α-5π)+2sin(3π-α)]/[csc(3π+α)+sec(5π+α)] sin²π/2=?还有类似的,比如cos²π/2,tan、cot、sec、csc,还有sinπ、ta (tan＾2α－cot＾2α)/(sin＾2α－cos＾2α)＝sec＾2α•csc＾2α 一道三角函数证明题~求证:(sinα+cscα)^2+(cosα+secα)^2=tan^2α+cot^2α+7 化简tanα(cosα-sinα)+(sinα+tanα)/(cotα+cscα)