大师作文网1/(1*2)+1/(2*3)+1/(3*4)+.1/(2007*2008)=?
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1/(1*2)+1/(2*3)+1/(3*4)+.1/(2007*2008)=?
将(2-1)/1*2断开,变成两个分式相减
(2-1)/1*2=2/1*2 - 1/1*2
在约分
=1-1/2
同样的,(3-2)/2*3=3/2*3 - 2/2*3 = 1/2 - 1/3
所以最后是
(1-1/2) + (1/2-1/3) + (1/3-1/3) + ...+ (1/2007-1/2008)
因为是加法,所以可以把括号全部拿掉
就是1-1/2+1/2-1/3+1/3-...+1/2007-1/2008=1-1/2008=2007/2008
(2-1)/1*2=2/1*2 - 1/1*2
在约分
=1-1/2
同样的,(3-2)/2*3=3/2*3 - 2/2*3 = 1/2 - 1/3
所以最后是
(1-1/2) + (1/2-1/3) + (1/3-1/3) + ...+ (1/2007-1/2008)
因为是加法,所以可以把括号全部拿掉
就是1-1/2+1/2-1/3+1/3-...+1/2007-1/2008=1-1/2008=2007/2008
1-(1/2-1/3)-(1/3-1/4).-(1/2007-1/2008)=?
1/1*2+1/2*3+1/3*4+1/4*5.+1/2007*2008+1/2008*2009=?
1/(1*2)+1/(2*3)+1/(3*4)+.1/(2007*2008)=?
1/(1*2)+1/(2*3)+1/(3*4)+.1/(2007*2008)=
1\(2\3)\(3\4)\.\(2007\2008)
|1-1/2|+|1/2-1/3|+|1/3-1/4|+……|1/2007-1/2008|=?
(-1)+2+(-3)+4+(-5)+.+(-2007)+2008
-1-2-3-4-5-...-2007-2008
初一数学计算题1/1*2+1/2*3+1/3*4+1/4*5+.+1/2007*2008=?
1/2009-1/2008|+|1/2008-1/2007|+|1/2007-1/2006|+.+|1/3-1/2|+|
|2009/1-2008/1|+|2008/1-2007/1|+|2007/1-2006/1|+.+|3/1-2/1|+
计算:|1/2-1|+|1/3-1/2|+|1/4-1/3|+...+|1/2008-1/2007|+|1/2009-1