y=x^2+3x+1 求dy

y=x^2+3x+1 求dy y=x^2x,求dy x^2+xy+y^3=1,求dy/dx y=f[(x-1)/(x+1)],f'(x)=arctanx^2,求dy/dx,dy y=sin(x^2),求dy/d(x^3) y=sin^2 {x/(x+1)} 求dy 1,y=e^tanxcos^3x,求dy 2,函数y=y（x）由方程e^(x+y)+arctan(xy)=0确定,求dy 求微分方程通解dy/dx=(x-2y+1)/(2x+3y+2) 求微分方程通解：dy/dx=(x-y+1)/(x+y^2+3) 求初值：dy/dx+y/x=x+1/x,当x=2,y=3 设y=（x/1-x)^x,求dy/dx 设y=(2+x)^x,(x>0) ,求dy