三角函数极限题Limit,x -> 0 {Cos[Sin(x)] - Cos(x)} / (Sin(x))^4答案是1/
三角函数极限题Limit,x -> 0 {Cos[Sin(x)] - Cos(x)} / (Sin(x))^4答案是1/
sin(x)cos(x)的极限是多少
求极限x趋于0时(1-cos(x/2))x / (tan x-sin x)
求极限 x趋近于零 1/sin^2(x)--cos^2(x)/x^2 答案是三分之四
sin(1/x)-cos(1/x)/x
求极限1/(sin*2x)-1/{x*2 (cos*2x)} x--0 当分子化成x*2 cos*2x-sin*2 x时
三角函数证明及化简题1.证明sin^6x+cos^6x=(sin^2x+cos^2x)(cos^4x-cos^2xsin
化简[1-(sin^4x-sin^2cos^2x+cos^4x)/(sin^2)]+3sin^2x
sin(sin(sin(sin(x)=cos(cos(cos(cos(x),X等于多少?
根号(1-cos x)/(没根号)sin x求x趋向0的极限.
三角函数求导题如何证明cos x的导数是-sin x
三角函数已知P(-4,3) 求(cos((π/2)+x)sin(-π-x))/(cos((11π/2)-x)sin((9