希望杯的一个问题if the ratio of the degree of exterior angle of∠A,∠B
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希望杯的一个问题
if the ratio of the degree of exterior angle of∠A,∠B and ∠C.that are in the triangle ABC is 5:4:3,then the ratio of the degree of ∠A,∠B and ∠C is( ).
(A)5:4:3 (B)3:4:5 (C)1:2:3 (D)3:2:1
当x≠-5/b时,(a+x)/(-bx-5)成立,则a^2-b^2=( ).
(A)0 (B)1 (C)99.25 (D)99.75
If a-b+c>0,then ( ).
(A)b(a+c)>b^2 (B)(a+c)^2>b(a+c) (C)1/(a+c)<1/b (D)(a+c)^5>b^5
if the ratio of the degree of exterior angle of∠A,∠B and ∠C.that are in the triangle ABC is 5:4:3,then the ratio of the degree of ∠A,∠B and ∠C is( ).
(A)5:4:3 (B)3:4:5 (C)1:2:3 (D)3:2:1
当x≠-5/b时,(a+x)/(-bx-5)成立,则a^2-b^2=( ).
(A)0 (B)1 (C)99.25 (D)99.75
If a-b+c>0,then ( ).
(A)b(a+c)>b^2 (B)(a+c)^2>b(a+c) (C)1/(a+c)<1/b (D)(a+c)^5>b^5
我十分对不起,我英语的看不懂,但中文的还能解答.
当x≠-5/b时,(a+x)/(-bx-5)成立,则a^2-b^2=( D ).
(A)0 (B)1 (C)99.25 (D)99.75
答案为:D
当x≠-5/b时,(a+x)/(-bx-5)成立,则a^2-b^2=( D ).
(A)0 (B)1 (C)99.25 (D)99.75
答案为:D
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