数学题 lim(an^2+bn-100)/(3n-1) =2 求ab的值大神们帮帮忙
数学题 lim(an^2+bn-100)/(3n-1) =2 求ab的值大神们帮帮忙
等差数列{an},{bn}的前n项和分别为An,Bn,切An/Bn=2n/3n+1,求lim(n→∞)an/bn
高二的极限运算题 lim(2an+4bn)=8,lim(6an-bn)=1,求lim(3an+bn)的值 n趋向于无穷大
等差数列an,bn的前n项和分别为Sn,若Sn/Tn=2n/(3n+1),求lim an/bn
若lim(2n+(an^2-2n+1)/(bn+2))=1 求a/b的值
已知lim n→无穷 (an^2+bn+5)/(3n-2)=2,求a,b的值
已知lim(3An+4Bn)=8,lim(6An-Bn)=1,求lim(3An+Bn)的值
1 lim[2n+1-根号(an^2+bn+1)]=2 求a b的值
已知{an},{bn}均为等差数列,前n项的和为An,Bn,且An/Bn=2n/(3n+1),求a10/b10的值
已知lim[(3n^2+cn+1)/(an^2+bn)-4n]=5,求常数a、b、c的值
lim (n→∞) [(an^2+bn+c)/(2n+5)]=3,求a,b
lim(n->无穷)[(3n^2+cn+1)/(an^2+bn)-4n]=5