①(2x+y-3)²②(3x+2y-4)(3x+2y+4)这两道题怎么算?
①(2x+y-3)²②(3x+2y-4)(3x+2y+4)这两道题怎么算?
已知x-y=1,y≠0,求{(x+2y)²+(2x+y)(x+4y)-3(x+y)(x-y)}÷y的值.
1.((y+2x)(-2x+y)+4(x+2y)^2)/3y 2.(2(x-y)^3-8(x-y)^2(x+y)+6y(
(3x-y)²-2x(4x-5y)-(x+2y)²
(X-3Y)(X+3Y)-(X+2Y)(X-4Y)-(2X-Y)2的平方
计算:(3x-4y)-[-(2y+x)+(x-3y)]-6x
若x+y=4,则多项式½(x+y)+4﹙x-y)-3(x-y)-3/2(x+y)-x+y是多少?
先化简,再求值:【(X+2Y)(X-2Y)-(X+4Y)平方]除4Y,其中X=-2,Y=-3
计算:(1)2/(x+y)+4y/x²-y²(2)x²/x+y-x+y
计算:(4y分之3x²)² × 3x分之2y + 2y²分之x² ÷ x分之2y
该怎么画出y=2(x+2)²+1,y=- 3/4(x-3)²+2.y=x²-x-2,y=-
已知x,y为实数,且2(x+2y)=x²+y²+5求代数式3x-4y分之x²+y²