main ( ) { int k=1,n=263 ; do { k*= n%10 ; n/=10 ; } while (
main ( ) { int k=1,n=263 ; do { k*= n%10 ; n/=10 ; } while (
#include main() {int n=2,k=0; while(k++ && n++ >2); printf("
以下程序的输出结果是 .main() { int k,n,m;n=10;m=1;k=1; while(k++
main() { int k=5,n=0; while(k>0) { switch(k) { default :brea
#include void main() { int k=5,n=0; while(k>0) {switch(k) {d
#include int main() { int n,a,sum=1,k; scanf("%d",&n); for(k
int jsValue(long n) {long int s=0,k; k=n; while(k) { s=s*10+
有以下程序 Main() {int k=5,n=0; do {switch(k) {case1:case3:n+=1;
Main() {int k=5,n=0; do {switch(k) {case1: case3:n+=1; break
运行下面程序段后,k值为(36).k=1;n=263; do {k*=n%10;n/=10; } while(n); 请
main() { int n=4; while(n--) printf("%d",--n); }
#include void main() { int k=-1; printf("%d,%u\n",k,k); }