The population,P(t),of China,† in billions,can be appr
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The population,P(t),of China,† in billions,can be approximated by
P(t) = 1.267(1.007)t,
where t is the number of years since the start of 2000.
According to this model,how fast was the population growing at the
start of 2000 and at the start of 2008?Give your answer in millions of people per year.(Use
h = 0.1,0.01,0.001,0.0001,and so on.Round your answers to two decimal places.)
beginning of 2000 ,million people per year
beginning of 2008,million people per year
运用极限 lim [f(a+h)-f(a)]/h
h→0
P(t) = 1.267(1.007)t,
where t is the number of years since the start of 2000.
According to this model,how fast was the population growing at the
start of 2000 and at the start of 2008?Give your answer in millions of people per year.(Use
h = 0.1,0.01,0.001,0.0001,and so on.Round your answers to two decimal places.)
beginning of 2000 ,million people per year
beginning of 2008,million people per year
运用极限 lim [f(a+h)-f(a)]/h
h→0
写出来就可以了,举个例子如h=0.1,2008年增速为:P(8.1)-P(8.0)/0.1=[1.267*1.007^(8.1)-1.267*1.007^(8.0)]/0.1=1.267*1.007^(8.0)*{(1.007^0.1-1)/0.1},你用计算器按一下,去试试看
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