设等差数列{an}的前n项和为Sn,等比数列{bn}的前n项和为Tn,已知bn>0(n∈N*),a1=b1=1,a2+b
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设等差数列{an}的前n项和为Sn,等比数列{bn}的前n项和为Tn,已知bn>0(n∈N*),a1=b1=1,a2+b3=a3,S5=5(T3+b2).
(Ⅰ)求数列{an},{bn}的通项公式;
(Ⅱ)求和:
(Ⅰ)求数列{an},{bn}的通项公式;
(Ⅱ)求和:
b
(Ⅰ)设{an}的公差为d,数列{bn}的公比为q,则
∵a1=b1=1,a2+b3=a3,S5=5(T3+b2), ∴q2=d,1+2d=1+2q+q2, ∴q2-2q=0, ∵q≠0,∴q=2,∴d=4 ∴an=4n-3,bn=2n-1; (Ⅱ)∵ bn TnTn+1= bn+1 qTnTn+1= 1 q( 1 Tn− 1 Tn+1) ∴ b1 T1T2+ b2 T2T3+…+ bn TnTn+1= 1 q( 1 T1− 1 T2+ 1 T2− 1 T3+…+ 1 Tn− 1 Tn+1) = 1 q( 1 T1− 1 Tn+1)= 1 q(1- 2 2n+1−1).
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