ysinx+cos(x-y)=0,求dy/dx|(x=π/2)

ysinx-cos(x+y)=0,求 dy/dx ysinx+cos(x-y)=0,求dy/dx|(x=π/2) 已知ysinx-cos(x+y)=0,求在点(0,π)的dy/dx值 已知ysinx-cos(x+y)=0,求在点(0,π/2)的dy/dx值 ysinX=cos(X—y)求导数dy/dX 由方程ysinx-cos(x+y)=0确定隐函数y(x),求dy|(0,π/2) 求由方程ysinx-cos(xy)=0所确定的隐函数y=y(x)的导数dy/dx 求函数的微分或导数!1,设ysinx-cos(x-y)=0,求dy解利用一阶微分的形式的不变性求得d(ysinx)-dc dy/dx=-(2xcosy+y^2*cosx)/(2ysinx-x^2*siny) 求解微分方程y'cosx+ysinx=0 求解微分方程dy/dx=y/（x+y的平方） y= (cos x)^x,求dy/dx 对于x=cos(y/x),求dy/dx.