请问为什么(1-sinx)/cosx = tan(x/2)?
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请问为什么(1-sinx)/cosx = tan(x/2)?
错了.
(1 -sinx)/cosx = [ 1 -tan (x/2) ] / [ 1 +tan (x/2) ].
应该是:
(1 -cos x) /sin x = tan (x/2),
或:
sin x /(1 +cos x) = tan (x/2).
= = = = = = = = =
1.(1 -cos x) /sin x = tan (x/2).
证明:因为 cos x =1 -2 [ sin (x/2) ]^2,
sin x = 2 sin (x/2) cos (x/2),
所以 (1 -cos x) /sin x = 2 [ sin (x/2) ]^2 / [ 2 sin (x/2) cos (x/2) ]
= sin (x/2) / [ cos (x/2) ]
= tan (x/2).
= = = = = = = = =
2.sin x /(1 +cos x) = tan (x/2).
证明:因为 sin x = 2 sin (x/2) cos (x/2),
cos x = 2 [ cos (x/2) ]^2 -1,
所以 sin x /(1 +cos x) = ...=tan (x/2).
= = = = = = = = =
同理,
(1 +cos x) /sin x =sin x /(1 -cos x) = cot (x/2).
cos x = [ cos (x/2) ]^2 -[ sin (x/2) ]^2
= 1 -2 [ sin (x/2) ]^2
= 2 [ cos (x/2) ]^2 -1,
公式的选取很关键.
(1 -sinx)/cosx = [ 1 -tan (x/2) ] / [ 1 +tan (x/2) ].
应该是:
(1 -cos x) /sin x = tan (x/2),
或:
sin x /(1 +cos x) = tan (x/2).
= = = = = = = = =
1.(1 -cos x) /sin x = tan (x/2).
证明:因为 cos x =1 -2 [ sin (x/2) ]^2,
sin x = 2 sin (x/2) cos (x/2),
所以 (1 -cos x) /sin x = 2 [ sin (x/2) ]^2 / [ 2 sin (x/2) cos (x/2) ]
= sin (x/2) / [ cos (x/2) ]
= tan (x/2).
= = = = = = = = =
2.sin x /(1 +cos x) = tan (x/2).
证明:因为 sin x = 2 sin (x/2) cos (x/2),
cos x = 2 [ cos (x/2) ]^2 -1,
所以 sin x /(1 +cos x) = ...=tan (x/2).
= = = = = = = = =
同理,
(1 +cos x) /sin x =sin x /(1 -cos x) = cot (x/2).
cos x = [ cos (x/2) ]^2 -[ sin (x/2) ]^2
= 1 -2 [ sin (x/2) ]^2
= 2 [ cos (x/2) ]^2 -1,
公式的选取很关键.
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