java.sql.SQLException:Parameter index out of range (1 > numb
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java.sql.SQLException:Parameter index out of range (1 > number of parameters,which is 0).
private int check(String user_name,String user_code) throws SQLException {
\x05\x05// TODO Auto-generated method stub
\x05\x05PreparedStatement stmt = null;
\x05String sql ="select * from log where name='?' and code='?';";
\x05stmt = Server.con.prepareStatement(sql);
\x05stmt.setString(1,user_name);
\x05stmt.setString(2,user_code);
\x05if(stmt.executeQuery(sql)==null){
\x05\x05return 0;
\x05}
\x05 return 1;
\x05}
private int check(String user_name,String user_code) throws SQLException {
\x05\x05// TODO Auto-generated method stub
\x05\x05PreparedStatement stmt = null;
\x05String sql ="select * from log where name='?' and code='?';";
\x05stmt = Server.con.prepareStatement(sql);
\x05stmt.setString(1,user_name);
\x05stmt.setString(2,user_code);
\x05if(stmt.executeQuery(sql)==null){
\x05\x05return 0;
\x05}
\x05 return 1;
\x05}
String sql ="select * from log where name='?' and code='?';";改成
String sql ="select * from log where name=?and code=?“;
再问: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '? and code=?' at line 1
再答: String sql ="select * from log where name=? and code=?";
String sql ="select * from log where name=?and code=?“;
再问: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '? and code=?' at line 1
再答: String sql ="select * from log where name=? and code=?";
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