亲们,请问lim sin(1/x)/(1/x)= x趋向于0
亲们,请问lim sin(1/x)/(1/x)= x趋向于0
lim(x趋向0)ln(1+sin x)/x^2
lim(x趋向正无穷)[x]*sin(1\x)=?
求极限lim(x趋向于0)ln(1+x^2)/sin(1+x^2)
lim(x趋向于0)(1+sinx-cosx)/(1+sinβx-cosβx)
lim(x趋向于0)sinx/x=1,那么lim(x趋向于0)x/sinx=?怎么算?
lim(x趋向于正无穷)(x*sin(1/x))=0 怎么用定义证明?
lim(1+e^1/x)^x,x趋向于+0
lim(x趋向于正无穷大时)[sin√(x+1)-sin√x]
x趋向于无穷时 lim (3x-1)/(x^3 乘以 sin(1/x^2 ))
lim(x趋向于0)(cosx)^[1/(xsinx)]=
极限lim【sin(x+π)】/x x趋向于0 就能推出lim【sin(x+π)】/x =lim(-sinx)/x =-