{x+y+z=6,2x-y+z=3,3x+9y+z=24

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x+y+z=6 (1)
2x-y+z=3 (2)
3x+9y+z=24 (3)
(1)-(2)得：2y-x=3 (4)
(3)-(1)得：2x+8y=18 即x+4y=9 (5)
(4)+(5)得：6y=12 y=2代入 (4)得 x=1,代入（1）得z=3.
故得：x=1,y=2,z=3.

试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y) {x+y+z=6,2x-y+z=3,3x+9y+z=24 x/2=y/3=z/5 x+3y-z/x-3y+z 如果|x+y+z-6|+|2x+3y-z-12|+|2x-y-z|=0求x,y, 解方程组2x+y-3z=1,x-2y+z=6,3x-y+2z=9求x,y,z的值 (x+y-z)(x-y+z)= 已知x,y,z 大于0,x+y+z=2,求证 xz/y(y+z)+zy/x(x+y)+yx/z(z+x)大于等于2/3 x=y/z=z/3,x+y+z ＝12,求2x+3y+4z是多少, 1.x+y=16,y+z=12,z+x=102.3x-y+z=4,2x+3y-z=12,x+y+z=63.x+y+z=6 3x+2y+z=9,x+y+2z=0,2x+3y-z=11 x+y+z=4 2x+3y-z=6 3x+2y+2z=10 2x-y+2z=-17 3x+y-3z=-4 x+y+z=6