解三元一次方程组x+2+y+z=10,2x+3y-z=3,3x+2y+2z=17
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解三元一次方程组x+2+y+z=10,2x+3y-z=3,3x+2y+2z=17
x+2+y+z=10,
{2x+3y-z=3,
3x+2y+2z=17
x+2+y+z=10,
{2x+3y-z=3,
3x+2y+2z=17
x+2+y+z=10,------- ①
2x+3y-z=3,------- ②
3x+2y+2z=17------- ③
①+②
3x+4y+2 = 13
3x+4y = 11------- ④
②×2 + ③
7x+8y = 23------- ⑤
⑤×2 - ④
x = 1
代入④
3 + 4y = 11
y = 2
将x = 1、y = 2代入①
1+2+2+z = 10
z = 5
2x+3y-z=3,------- ②
3x+2y+2z=17------- ③
①+②
3x+4y+2 = 13
3x+4y = 11------- ④
②×2 + ③
7x+8y = 23------- ⑤
⑤×2 - ④
x = 1
代入④
3 + 4y = 11
y = 2
将x = 1、y = 2代入①
1+2+2+z = 10
z = 5
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