2log底3x+log底3 2=1/2log底3 16 x为什么值
2log底3x+log底3 2=1/2log底3 16 x为什么值
4^log(4)[x^2]+3^log(9)[6x]=log(2)[16]
log的数学题2 + log 2(为底)4= 3x-1
log以5为底(3x-2)>log以5为底(x+1)
log以2为底的(log以3为底的(log以4为底的x))=log以3为底的(log以4为底的(log以2为底的y))=
已知log(1/7)[log(3)(log(2)x)]=0
log(0.5x)(2)-log(0.5x^3)(x^2)=log(0.5x^3)(4)
换底公式的使用!为什么 y=log(1/2) X = - log(2)X
已知log(2)[log(3)(log(4) x)] = log(3) [log(4) (log(2) y)]=0,求x
log底数7[log底数3(log底数2X)]=0,那么x^1/2的值是
2 log(3x)= log 4 +log(6-x)怎么求...急
1/log(2)x+1/log(3)x+1/log(4)x=1,x=?