LINGO求解错误MODEL:SETS:CITY/1..5/:U;LINK(CITY,CITY):COST,X;ENDS
来源:学生作业帮 编辑:大师作文网作业帮 分类:数学作业 时间:2024/09/21 18:34:16
LINGO求解错误
MODEL:
SETS:
CITY/1..5/:U;
LINK(CITY,CITY):COST,
X;
ENDSETS
DATA:
COST= 0 120 250 330 210
120 0 98 350 225
250 98 0 520 430
330 350 520 0 270
210 225 430 270 0
ENDDATA
N=@SIZE(CITY);
MIN=@SUM(LINK:COST*X);
@FOR(CITY(K) :
@SUM(CITY(I)|I #NE# K:X(I,K))=1;
@SUM(CITY(J)|J #NE# K:X(K,J))=1;
@FOR(CITY(J)|J #GT# 1 #AND# J #NE# K:
U(J)>=U(K)+X(K,J)-(N-2)*(1-X(K,J))+(N-3)*X(J,K)););
@FOR(LINK:@BIN(X));
@FOR(CITY(K)|K #GT# 1:
U(K)<=N-1-(N-2)*X(1,K);
U(K)>=1+(N-2)*X(K,1));
END
MODEL:
SETS:
CITY/1..5/:U;
LINK(CITY,CITY):COST,
X;
ENDSETS
DATA:
COST= 0 120 250 330 210
120 0 98 350 225
250 98 0 520 430
330 350 520 0 270
210 225 430 270 0
ENDDATA
N=@SIZE(CITY);
MIN=@SUM(LINK:COST*X);
@FOR(CITY(K) :
@SUM(CITY(I)|I #NE# K:X(I,K))=1;
@SUM(CITY(J)|J #NE# K:X(K,J))=1;
@FOR(CITY(J)|J #GT# 1 #AND# J #NE# K:
U(J)>=U(K)+X(K,J)-(N-2)*(1-X(K,J))+(N-3)*X(J,K)););
@FOR(LINK:@BIN(X));
@FOR(CITY(K)|K #GT# 1:
U(K)<=N-1-(N-2)*X(1,K);
U(K)>=1+(N-2)*X(K,1));
END
cost的最后要加分号
LINGO求解错误MODEL:SETS:CITY/1..5/:U;LINK(CITY,CITY):COST,X;ENDS
一个LINGO MODEL:SETS:CITY/1..14/:JL;STEP/1..11/;LINE( STEP,CIT
city
lingo错误求解model:sets:kinds/1..10/:c_p,d,v,Q,s,N;fa/A1,A2,A3/:
lingo查错model:sets:kinds/1..10/:v,Q,s,N,c_p,d,p;fa/1..3/;link
lingo程序求解model:sets:jingkou/1..9/:n;zuobiao/1,2/;links(jingk
lingo 错误 model:sets:warehouses/1..6/:capacity; vendors/1..3/
lingo错误model:sets:quarter/1..4/:DEM,RP,OP,INV;endsetsdata:DE
lingo报错,MODEL:sets:fac/a1..a49/:Fcus/b1..b49/;link(fac,cus):
LINGO编程错误model:sets:C1/1..3/:; C2/1..8/:; C3/1..7/:; S1/1..1
lingo语句求解析sets: demand/1..6/:a,b,d; supply/1..2/:x,y,e; link
visit dead city 5