x=1; y=2; z=3; x+=y+=z; cout

x=1; y=2; z=3; x+=y+=z; cout int x=1,y=2,z=3; x=x^z; y=y^z; z=x^y; cout int x=10,y=3,z; cout int w=1,x=2,y=3,z=4; cout int c=7,d=8,z=3,a,x,y; a=c^d; x=c^d&-z; y=a&-z; cout 试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y) (x+y-z)(x-y+z)= x/2=y/3=z/5 x+3y-z/x-3y+z 3道高数题,1,函数F(x,y,z)=(e^x) * y * (z^2) ,其中z=z(x,y)是由x+y+z+xyz= {x+y+z=1;x+3y+7z=-1;z+5y+8z=-2 x+2y=3 x+y+z=36 2x+y+z=15 2y=3z x-y=1 x+2y+z x-z=-1 2x+z-y=1 如果,根号x-3+| y-2 |+z^2=2z-1 求 （x+z)^y