△ABC的三个内角A、B、C所对的边分别为a、b、c,asinAsinB+bcos^2A=根号2a. 若C^2=b2^+
来源:学生作业帮 编辑:大师作文网作业帮 分类:数学作业 时间:2024/09/24 01:24:57
△ABC的三个内角A、B、C所对的边分别为a、b、c,asinAsinB+bcos^2A=根号2a. 若C^2=b2^+根号3a^2,求B.
sinA=asinB
asinAsinB+bcos^2A=√2a
bsin²a+bcos²A=√2a
b=√2a
b^2=2a^2
c^2=b^2+√3a^2
=2a^2+√3a^2
c=a√[2+√3]
=a√[(4+2√3)/2]
=a(√3+1)/√2
cosB=(a^2+c^2-b^2)/(2ac)
=(a^2+2a^2+√3a^2-2a^2)/[2a*(√3+1)a/√2]
=(1+√3)a/√2(√3+1)a
=√2/2
所以 B=45°
asinAsinB+bcos^2A=√2a
bsin²a+bcos²A=√2a
b=√2a
b^2=2a^2
c^2=b^2+√3a^2
=2a^2+√3a^2
c=a√[2+√3]
=a√[(4+2√3)/2]
=a(√3+1)/√2
cosB=(a^2+c^2-b^2)/(2ac)
=(a^2+2a^2+√3a^2-2a^2)/[2a*(√3+1)a/√2]
=(1+√3)a/√2(√3+1)a
=√2/2
所以 B=45°
△ABC的三个内角A、B、C所对的边分别为a、b、c,asinAsinB+bcos^2A=根号2a. 若C^2=b2^+
△ABC三个内角A,B,C所对边分别为a,b,c,asinAsinB+bcos²A=根号2×a,b/a=根号2
△ABC三个内角A,B,C所对边分别为a,b,c,asinAsinB+bcos²A=根号2×a,则b/a等于?
△ABC的三个内角A B C的对边分别为a b c,asinAsinB+bcos^2A=根号下2a 若c2=b2+根号3
三角形ABC的三个内角A,B,C所对的边分别是a,b,c,asinAsinB+bcos²A=根号2(找不到符号
在三角形ABC的三个内角A,B,C所对的边分别为a,b,c,asinAsinB+bcos^2A=√2a.(1)求
在三角形ABC的三个内角A、B、C所对的边分别为a、b、c,若asinAsinB+bcos平方A=根号2·a,则b/a=
△ABC的三个内角A,B,C所对的边分别为a,b,c,asinAsinB+bcos^2A=√2a,求b/a.若c^2=b
△ABC的三个内角A,B,C所对的边分别为a,b,c,asinAsinB+bcos2A= 根号2乘以a ,则 b/a=
ΔABC的三个内角A,B,C所对的边分别为a,b,c,asinAsinB+bcos^2A=√2a 1.求b/a 2.若c
△ABC的三个内角A,B,C所对的边分别为a,b,c,asinAsinB+bcos²A=2a,(1)求b/a,
三角形abc的三个内角a,b,c所对的边分别为a,b,c,asinasinb+bcos2a=根号2a.