(1+x*x)dy=(1+xy)dx y|x=0=1怎么算
(1+x*x)dy=(1+xy)dx y|x=0=1怎么算
x^2+xy+y^3=1,求dy/dx
dy/dx=1+x+y^2+xy^2
设 e^(x+y) - xy = 1,求 dy/dx \ x=0 y=0
下面都是求微分方程的通解:1、(y^-2xy)dx+x^2dy=0 2、(x^2+y^2)dy/dx=2xy 3、xy’
求(xy^2+x)dx+y(1+x^2)dy=0的通解
微分方程 xy-1/x^2y dx - 1/xy^2 dy =0
dy/dx = 1/x-y
dy/dx=x(1-y)
dy/dx=xy/(x^-y^)满足条件y(0)=1特解为,
微分方程 (dy/dx)-(y-1)(xy-y-x)=0岛国考研数学题 就教
dy/dx,y=(1+x+x^2)e^x