2 2(y-2013) +(y-2010) =4035则(y-2013)(y-2010)=?
2 2(y-2013) +(y-2010) =4035则(y-2013)(y-2010)=?
[x(x-y)-y(x-y)+(x+y)(x-y)]÷2x其中x=2012 y=2013
2y''+y'-y=0
1.5y+8y-6y=2y-3
先化简,在求值:6y-(y+2分之y + 2-y分之y)除以y³-4y-2y²+8分之y,其中y=
(y^2-3y+2)(y^2+3y-2)=y^2(y+3)(y-3)
先化简,再求值 (1)[(x-y)的平方+(x+y)(x-y)]÷2x 其中X=2010,y=2009 (2)y(x+y
若(x-y)/(x+y)=3 则(x+2y)/(6x-7y)等于
解方程3y^2-(2y+1)(y-2)=(y-5)(y-1)
解分式方程 2/y-y/(y-2)=4/(y²-2y)
解微分方程 y'=[e^(y^2)]/2xye^(y^2)+4y,y|(x
(-y+5+4y^2)-(-y^2+5y-4),其中y=-2