1.已知x²+y²+7 xy+-2求5x²-3xy-4y²-11xy-7x

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1.已知x²+y²+7 xy+-2求5x²-3xy-4y²-11xy-7x²+2y²的值
1.已知x²+y²+7 xy+-2求5x²-3xy-4y²-11xy-7x²+2y²的值

5x²-3xy-4y²-11xy-7x²+2y²
=-2x²-2y²-14xy
=-2(x²+y²)-14xy
=-2×7-14×(-2)
=-14+28
=14

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