f(x)=1/3ax^3+bx^2+cx(a
已知函数f(x)=1/3ax^3+1/2bx^2+cx(a>0).
f(x)=1/3ax^3+bx^2+cx(a
设函数f(x)=1/3ax^3+bx^2+cx(a
设函数f(x)=1/3*ax;+bx;+cx(a
设三次函数f(x)=ax^3+bx^2+cx+d(a
三次函数f(x)=ax^3+bx^2+cx(a,b,c∈R)
设f(x)=ax^3+bx^2+cx+d,(a
1已知f(x)=ax^2+bx+c(a≠0)是偶数,试判断函数g(x)=ax^3+bx^2+cx的奇偶性
若(2x-1)^5=ax^5 + bx^4 + cx^3 + dx^2 + ex + f
已知:(2x-1)^5=ax^5+bx^4+cx^3+dx^2+ex+f
设(2x-1)^5=ax^5+bx^4+cx^3+dx^2+ex+f
(2x-1)^5=ax^5+bx^4+cx^3+dx^2+ex+f