12%X=X-(15*10+12.5*40)
X/15 + X/12 + X/10 = 1365,求X,
12%X=X-(15*10+12.5*40)
1x+2x+3x+4x+5x+6x+7x+8x+9x+10x+11x+12x+13x+14x+15x=550
解方程 40%x+2=12 x+25%x=10 x-30%x=1.4 15x-60=240 x+1
(x+12)(x-2)+(x+7)(x+8)-(x+5)(x-10),其中x=2
(2x^-5x+2/6x^+13x+6)*(6x^-5x-6/6x^-17x+10)*(12x^+8x-15/2x^-x
x+x=x+15
(12x-10)/21+(7x-9)/20=(2-x)/15+(8x-9)/12
已知x/15+x/12+x/10=1365,求x
帮我解一下下题:12%X=X-(15*10+12.5*40)
2x-10=15x+30,6x-6=6x+2,9-3x=2x-8,5x=9x-50 ,5y-5=12-6y,15x-9=
x/(x/12+x/15)*(x/12-x/15)=60