若x^2+9y^2-2x+12y+5=0,试求y^2的值

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x^2+9y^2-2x+12y+5=0
x^2-2x+1+9y^2+12y+4=0
（x^2-2x+1)+〔(3y)^2+2*2*3y+2^2〕=0
(x-1)^2+(3y+2)^2=0
且 (x-1)^2≥0,(3y+2)^2≥0
所以x-1＝0,3y+2＝0
解得：y＝-2/3
所以y^2＝4/9

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