当x=-3/2时求整式(2x-1)²-(3x+1)(3x-1)+5x(x-1)
当x=-3/2时求整式(2x-1)²-(3x+1)(3x-1)+5x(x-1)
当x=2时,求整式x³-2x²-3-4/1(3x³+12x²-8x+4)的值.
当x=3时,求[(1/x²)-(2x-1/x²-4x+4)]÷2/x²-2x
当x=-(1/2)时,代数式(x)/)x+1)-【(x+3)/(x+1)】*【(2x²+6x)/(x²
当X>-1时,求f(x)=(x^2-3x+1)/(x+1)的值域
当X>-1时,求f(x)=x^2-3x+1/x+1的值域
(x/x-1)+(5x-2)/x*x-x=1 求x(有图)
已知3x-4除以(x-1)(x-4)=a除以x-1+b除以x-2 求整式a b
5x-3(2x+1)=6x-4(5-3x)求x
(1) x-3/x-2 - x-5/x-4=x-7/x-6 - x-9/x-8
求当x=1时,代数式x(x+3)分之1+(x+1)(x+4)分之1+(x+2)(x+5)分之1+...+(x+7)(x+
(1)当x=2时,求代数式2x²(x²-x+1)-x(2x³-10x²+2x)的