-{-[-(x-y)]}+{-[(x+Y)]}
-{-[-(x-y)]}+{-[(x+Y)]}
x(x-y)-y(y-x)+(x-y)²因式分解
{(x-y)²+(x+y)(x-y)}÷2x
因式分解x²(x-2y)+y²(2y-x)
分解因式(x+y)3次方-y(x+y)平方+x平方(y+x)
计算:(1)2/(x+y)+4y/x²-y²(2)x²/x+y-x+y
(y-x)的二次方(x-y)+(x-y)的三次方+2(x-y)的二次方(y-x)
已知x-y=1,y≠0,求{(x+2y)²+(2x+y)(x+4y)-3(x+y)(x-y)}÷y的值.
{(x,y) |x|+|y|
x>y?x:y
先化简,再求值:【(X+2Y)(X-2Y)-(X+4Y)平方]除4Y,其中X=-2,Y=-3
先化简,再求值:【(X+2Y)(X-2Y)-(X+4Y)平方]除4Y,其中X=5,Y=2